What is the solubility product of SrF2?

Question

Assume that the soulbility if SrF2 in water is 0.22 grams per liter of distilled water. What us the solubility product of SrF2? Molar mass of SrF2 is 125.62 grams/mole?

Answer 1

Ksp = [Sr++][F-]^2

0.22 g / 125.62 g/mol = 1.75x10^-3 mol

[Sr++] = 1.75x10^-3 M

[F-] = 3.50x10^-3 M

Ksp = 2.15x10^-8