What is the totel length of our orbit?

Question

What is the totel length of our orbit?

Answer 1

2*pie*1UA= 6.2830 UA

Answer 2

The average distance from the Earth to the Sun is 92,951,640 miles. This means that if the orbit of the Earth was circular instead of eliptical, the radius of the circular orbit of the Earth around the sun would be 92,951,640 miles. The circumfrence of that circle would be total length of the orbit.

Using geometry, the formula for finding the circumfrence of a circle is: Circumfrence = 2 x pi x Radius.

So, the total length of the Earth's orbit around the sun (in miles) is (approximately): 2 x 3.14 x 92,951,640.

This works out to 583,736,299 miles.

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Answer 3

The total length ofour orbit around the Sun is 966 million(96.6 crore) kilometers which is covered in 365 days 6hours 9mts and 30 sec. at a speed of 1600 k.m per minute.

Answer 4

The average distance from the Earth to the Sun is 92,951,640 miles.  This means that if the orbit of the Earth was circular instead of eliptical, the radius of the circular orbit of the Earth around the sun would be 92,951,640 miles.  The circumfrence of that circle would be total length of the orbit.

Using geometry, the formula for finding the circumfrence of a circle is: Circumfrence = 2  x  pi  x  Radius.

So, the total length of the Earth's orbit around the sun (in miles) is (approximately):  2  x  3.14  x  92,951,640.

This works out to 583,736,299 miles.

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Answer 5

From Perihelion to Perihelion? Or do you mean the total kilometer counter of Earth?

The first one is rather complex math, requiring to solve a infinite series. It can be approximated to 6.282746676 AU or 939.898 million km (with less than 1 m error caused by the approximated calculation)

The second can't be solved, because we can't tell for sure, how the orbit of Earth looked like in it's past.

Answer 6

The quick answer is that Earth is about 100 million miles from the Sun.  The orbital path is pi * 2 * r.  If pi is 3, then it's about 600 million miles. That's math one could do in their head.

Want more precision?

The semi major axis is 149,597,887.5 km.  If we model the orbit as a circle, then 149,597,887.5 km * 2 * 3.141592654 = 939,951,249 km = 584,058,630 miles. This matches the above estimate OK, so it's at least not very far wrong. The Earth's orbit is pretty close to a circle.

That's not good enough for you?  You can use the "very good" approximation from the Wiki ellipse page using 152,097,701 km for the semi-major axis and 147,098,074 km for the semi-minor axis. This yields 940,016,865 km = 584,099,400 miles.

In the Unix "bc" command, this math is:

scale=20

a=147098074

b=152097701

p=3.141592654

c=p*(3*(a+b)-(sqrt((3*a+b)*(a+3*b))))

c

That's not good enough?  You can use the full infinite series formula with the above numbers, and keep going until it converges to the number of digits you want.  But i'm convinced that we're already close to the number of digits known in the input numbers.