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What is the vertex of y= 2(x-2)^2 - 3? and y= -2x^2 - 3?

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What is the vertex of y= 2(x-2)^2 - 3? and y= -2x^2 - 3?

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  1. The first one can be rewritten as

    (y + 3) = 2(x - 2)^2, so the vertex is at (2,-3).

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