What is the vertical height between the two climbers? ______m?

Question

A rock climber throws a small first aid kit to another climber who is higher up the mountain. The initial velocity of the kit is 25 m/s at an angle of 62 degrees above the horizontal. At the instant when the kit is caught, it is traveling horizontally, so its vertical speed is zero.

Answer 1

Yey I miss Forces and motion questions...

well I'm going to resolve the vector triangle and find how fast the first aid kit is accelerating vertically.

cos28 x 25= the initial vertical velocity. which is... 22 m/s

then i'll use the equation

V(squared) = U(squared) + 2AS

I'll say the second climber is 24.6 metres higher.

Answer 2

what you have to do is to first determine the initial vertical speed of the kit, and then figure out how high this kit will travel given this initial vertical speed

first, find the initial vertical speed:

initial vertical speed=v0sin(theta)=25sin(62)=22m/s

second, how high will an object with this vertical speed climb; for this we use:

vf^2=v0^2+2ad where vf is final speed, v0 is initial speed, a is accel and d is distance traveled

vf=0, v0=22 m/s, a=-9.8 m/s/s and we are looking for d

substituting values:

0=22^2-2(9.8)d

d=24.7m

Answer 3

conservation of energy

E0 = E1

(1/2)mv^2 = mgh

h = v^2 / (2g)

v = 25 sin(62) = 22.07 m/s

h = (22.07)^2 / (2*9.8)   = 24.86 m