What is the volume in Liters of 0.50 mole of nitrogen gas (N2) at STP?

Question

a. 44.8 L

b. 1.0 L

c. 11.2 L

d. 22.4 l

Answer 1

It is known that one mole of any gas at STP occupies 22.4 liters. So 1/2 a mole would take up 11.2 L. Or if you want to do it the hard way:

PV = nRT ---> V = nRT/P

V = 0.50 x 0.08206Latm/molK x 273K/1 atm =

11.2L

Answer 2

The ideal gas equation can be used to solve this problem. The condition is in STP which means that the temperature is 0deg Celcius or 273.15K and pressure is 1atmosphere.

molar mass of nitrogen gas = 28g/mol

moles of N2 (n) = 0.5 mol

R = 0.0821 L-atm / mol-K

T = 273.15K

P = 1atm

PV = nRT

V = nRT / P

Volume = (0.5 mol x 0.0821 L-atm/mol-K x 273.15 K) / 1 atm

Volume = 11.2 L

The answer is:

C. 11.2 L