What is the x-intercept of this parabola?

Question

y= -x^2 +4x

Thanks!

Answer 1

y=0 =>

x=0, 4

/*************/

y= -x^2 +4x

0 = -x^2 +4x

x^2 = 4x

true when x = 0 or x = 4

Answer 2

there are two:

x-intercepts are where y = 0

0 = -x^2 + 4x

0 = x(-x + 4)

so x = 0 or (-x + 4) = 0 ==> x = 4

x intercepts: (0,0) and (4,0)

Answer 3

The x-intercept has to be zero; there is no constant to shift the parabola up or down from the origin.

Answer 4

The parabola has two x-intercepts.

Let y = 0, then solve for x.

0 = - x ^ 2 + 4x

0 =  - x ( x - 4 )

By the zero product property :

- x = 0  OR  x - 4 = 0

so x = 0  OR x = 4 <=== both are solutions

Good luck to you !