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What mass of naphthalene must be dissolved in 300.g of benzene to produce a solution with a freezing point ?

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2.5 degrees below that of pure benzene? Kf for benzene is 5.12 degreeC kg/mol.

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  1. dTemp = Kf (molality)

    2.5 = 5.12 (molality)

    molality = 0.488 molal

    which is 0.488 moles  naphthalene per 1 kg solvent

    which is (0.488 mol) (128.2 g/mol Naph) = 62.6 grams of Naph per kg solvent

    ? g naph = 0.300kg  benz @ 62.6 grams naph / 1 kg benz =

    your answer:18.8 grams of naphthalene

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