Question:

What pressure (in atm) will 0.44 moles of CO2 exert in a 2.6 L container at 25 degrees C?

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Please help! The only thing I've got is:

P=

V=

n= 0.44 moles

R= 0.08205

T= 25 + 273 = 298

Please help it make sense for me?!!!

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  1. You forgot that you have volume too :)

    Use the ideal gas law and solve for pressure:

    PV = nRT

    P = nRT/V

    P=

    V= 2.6 L

    n= 0.44 moles

    R= 0.08205

    T= 25 + 273 = 298 K

    Hope I helped :)

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