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Question

an object with mas 2.1 kg is pushed upward an inclined plane by a force F,as shown in figure.if the object moves with constant velocity,calculate

a)the force F

B)work done by the force F if the object moves on :

a plane with coefficient friction = 0.2

the figure u can view from this link

http://i21.photobucket.com/albums/b266/orizim/Image013.jpg

notes.distance = 2.65m

angle = 20 degree

Answer 1

sum of the forces are zero :

x : mg*sin(20)+Fk-F=0

y : mg*cos(20)-N=0

Fk= N*coefficient

mg*sin(20) + mg*cos(20)*coeff - F=0

F=10.9177(N)

F is constant

so

W=integral(F.dx)=F*integral(dx)

=10.9177*2.65= 28.932(j)