Whats the inverse and how?

Question

(x+3)/(1-x)

inverse please and how if you have time

Answer 1

Here's a good explanation...

http://www.mathclues.com/ModuleFindAnInv...

Hope this helps you!  Please email anytime for further questions.

Answer 2

f (x) = (x + 3) / (1 - x) = y

x + 3 = y - xy

x + xy = y - 3

x (1 + y) = y - 3

x = (y - 3) / (1 + y)

g (y) = x

g (y) = (y - 3) / (1 + y)

g (x) = (x - 3) / (1 + x)

f ^(-1) ( x ) = (x - 3) / (1 + x)

Answer 3

y = (x + 3)/(1 - x)

Solve for x:

(1 - x)y = (x + 3)

y - xy = x + 3

y - 3 = x + xy

y - 3 = x(1 + y)

x = (y - 3)/(1 + y)

Now interchange x and y:

y = (x - 3)/(1 + x)

Therefore, the above is your inverse.

Hope this helps!

Answer 4

(1-x)/(x+3)

Answer 5

To determine the inverse function g(x) = f^-1(x)

exchange y and x so  we get

x = (y+3)/(1-y)  next multiply both sides by 1-y

x(1-y) = y + 3

x -xy = y+ 3

add xy to both sides

x= xy+y+3

subtract 3 from both sides

x-3 = xy+y

use symmetric property of equality

xy + y = x-3

factor y from all terms on left side

y(x+1) = x-3

divide both sides by x+1

y = (x-3)/(x+1)

This result is g(x) = f^-1(x)