When 60.0ml of 3.0-molar K2CO3 is added to 40.0ml of 1.0-molar KHCO3 the resulting concentration of K+ is...?

Question

When 60.0ml of 3.0-molar K2CO3 is added to 40.0ml of 1.0-molar KHCO3 the resulting concentration of K+ is...?

Answer 1

Moles K2CO3 = 0.0600 L x 3.0 =0.180

Moles K+ = 2 x 0.180 = 0.360

Moles KHCO3 = 0.0400 L x 1.0 = 0.0400

total moles = 0.360 + 0.0400 =0.400

total volume = 40.0 + 60.0 = 100.0 mL => 0.100 L

[K+] = 0.0400 / 0.100 = 0.400 M

Answer 2

i think that its 1.5652mols/litre for K im not sure let me know if its correct or not plz