When playing roulette on a european table, what are the odds of black or red coming being spun 15 times row?

Question

When playing roulette on a european table, what are the odds of black or red coming being spun 15 times row?

Answer 1

Your question is moot as you can not bet on extended predictions only on each spin.

Answer 2

Again you people with the failure to consider every variable, although you were close with  2.023 x10^-5

the first trial doesnt matter as it will either be black or red, and that is the starting point, we will ignore the possibility of 0 for the first spin. since it woudl have no sigifigance in a streak of red or black.  After that the odds of getting black or red are the same so the probibility of 18/37 is only raised to the 14th power, not the 15th

the correct answer is   0.00004159:1

Answer 3

Well, of course the odds would be 1/2^15 if either black or red counted; 1/2^14 if the first throw didn't matter.  But on a European table, there is one green square, so the actual odds are either 18/37^14 or ^15.  An American table is much worse.

In any case, I wouldn't bet on it.

Answer 4

0.00202330668083902%

or 1 in 49424

Answer 5

In European Roulette the odds of it being black one time is 18/37=48.65%.  American Roulette it is 18/38=47.37%.

I found a web site that may answer your question.  On it they stated that the odds of getting the same color 18 times in a row is 1 in 693,745.

So the odds of 15 times would be a little better:

(18/38)^15=  Whatever that equals.