Question:

Where does -3x - 5y = 35 cross the y axis?

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i have to kno this for skool, gosh, hate it...

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  1. linear equations always have to be converted to the form

    Y=mX + b

    m is the slope

    b is the y intercept

    So, lets change your equation into the correct form by isolating the Y

    -3X-5Y=35

    move the -3X

    -5Y= 3X+35

    divide by 5

    -Y= 3/5X + 7

    multiply the whole equation by -1

    Y= -3/5X-7

    That means the slope is -3/5

    and the Y intercept is -7


  2. -3x - 5y=35

    +3x          +3x  (add 3x to both sides of the equation)

    -5y=3x + 35

    ___ __    ___ (now divide each part by -5)

    -5      -5      -5  (the 5s are supposed to be lined up under thelines)

    leaving you with....

    y=3/5x + -7    (this is tells you the slope of the line is 3/5 and the y-intercept is at -7)

  3. The line crosses the Y axis where x=0

    so -5y = 35

    -y = 7

    y = -7

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