Which best describes the relationship between the lines with equations 8x+y=6 and 16x+ 2y=0?

Question

please help, my choices are

a. perpendicular

b. parallel

c.samce line

d. neither parallel nor perendicular

Answer 1

B

2(8x +y) = 12

16x + 2y = 0

parallel

a is multiple of b ... with different constant solutions[not same line]

Answer 2

rearrange the equation in standard form like this:

y= 6 - 8x

y= (0/2) - (16/2)x

Look carefully.

Perpendicular == when one eqn has negative inverse slope of the other

Parallel==  when the two eqns share the same slope

wtf is a samce line?... don't bother. I don't care!

I think now you can solve the problem.

Answer 3

B. parallel

Their slopes are the same. If any two lines have the same slope, then they are parallel.

8x + y = 6

y = -8x +6

16x + 2y = 0

2y = -16x

y = -8x

Both lines have a slope of -8. Therefore, they're parallel.

Answer 4

Let's solve each in terms of y:

Line 1:

8x + y = 6

y = -8x + 6

Line 2:

16x + 2y = 0

2y = -16x

y = -16x / 2

y = -8x

These lines have the same slope (-8) but different y-intercepts (6 for line 1 and 0 for line 2).

Lines with the same slope but different intercepts are parallel.

Answer:

b. parallel

Answer 5

b. parallel

The slope is the same, the line is just shifted up or down 6 units