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Which of the following combinations of quantum numbers can refer to an electron in a ground-state cobalt atom

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a: n=4, l=2, m(sub)l = -2

or

b: n=3, l=1, m(sub)l = 0

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  1. The correct answer is b.

    a) refers to a 4d electron since l=2 means a d orbital. (l=0 is an s orbital, l=1 is a p orbital). Co has no 4d electrons, only 3d.

    b) refers to a 3p electron (allowed).

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