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Which of the following is the correct formula for titanium (III) sulfide?

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Ti3S

TiS3

Ti3S2

Ti2S3

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  1. The oxidation number of Ti (lll) is +3 and the oxidation number of sulfide (S) is -2.  So cross over and you have Ti2S3


  2. Ti2S3... Sulfur is -2, Ti is +3, so you just drop those numbers down/across, getting Ti2S3

  3. TiS3,because of exchange of radicals.Ti gives out 3 an S gives out 1.
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