Who knows how to solve these equations?

Question

a) __ Fe (s) + __S (s) → __ Fe2S3 (s)

b) __ P4 (s) + __ H2 (g) → __ PH3 (g)

c) __ NO (g) + __ Cl2 (g) → __ NOCl (g)

d) __ SiCl4 (l) + __ Mg (s) → __ Si (s) + __ MgCl2 (s)

How your work, it helps to understand what you did.

Answer 1

2 Fe(0)  + 3 S ------  Fe2S3

P4 + 6 H2 --------   4 PH3

2 NO + Cl2 --- 2 NOCL

SiCl4 + 2 Mg(0) ---------   2 MgCl2 + Si

Answer 2

a.  2Fe + 3S = Fe2S3

b.  P4 + 6H2 = 4PH3

c.  2NO + Cl2 = 2NOCl

d.  SiCL4 + 2Mg = Si + 2MgCl2

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http://misterguch.brinkster.net/eqnbalan...

If you give it your best shot and still can't get it, go to this site and assuming you have the proper subscripts, it will balance your equations for you:

http://adomas.org/bceq/

Answer 3

2Fe + 3S > Fe2S3

straightforward, balance atoms on both sides

P4 + 6 H2 > 4PH3

Abit more complicated due to the P4. same principle applies. equal amount of each elements on each side

2NO + Cl2 > 2NOCl

SiCl4 + 2Mg > Si +2MgCl2