Who wins? (Texas Hold'em)?

Question

if player one has a 9 of Hearts and a Q of Hearts, and player two has a K of Hearts and a J of Spades, and the cards on the table are an A of Hearts, 6 of Hearts, 3 of Hearts, 5 of Clubs, and a J of Hearts, who wins? do they split because the highest card is on the table? please help, and thanks in advance!

Answer 1

player two wins because his best five card is an ace, king, jack, 6, 3 flush.

player one has an ace, queen, jack, 9, 6 flush.

the highest card is an ace for both players so the next highest card decides it.  player two has a king and player one has a queen.

for future reference, it doesn't matter if the cards are on the table or in the player's hand, just compare each players best five card hand.

Answer 2

Player one wins

Answer 3

player two because he has the next highest card after the ace, and it does not matter if you have more than the required 5 for a flush so that would not matter on player one

Answer 4

In Texas Holdem, the best five handed hand wins.  The hand is made up of five community cards and two pocket cards.  You do not have to use your poket cards.

In your scenario, Player one has a flush of Ace, Queen, Jack, Nine, Six of hearts (the three on the board is lower than the other five)

Player two has what is called the nut flush (can't be beat) of Ace, King, Queen, Jack, Nine of hearts and wins the pot.

In flushes, the five highest cards are used to establish the best flush.

Player one would have one had a fourth heart not been put on the board, but unfortunately, it did.

Matt