MY QUESTION:
The equations are redox displacement reactions:
a) Bromine water is added to a solution of potassium iodide and the mixture is shaken.
MY ANS: Br (aq) + KI (aq) ---> KBr (aq) + I (s)
Br(aq) + I-(aq) ----> Br-(aq) + I(s)
Br is reduced, I is oxidised. But is this correct?
I had an answer:
a) Bromine is Br2(aq) and Iodine in solution is I3-, or I2(aq). Bromine will be reduced as iodine is oxidized to I2. Potassium is indeed a spectator ion. The typical "molecular equaiton".
Br2(aq) + 2KI(aq) --> 2KBr(aq) + I2(aq)
or the ionic equation
Br2(aq) + 3I- --> Br- + I3-
First of all i never knew there was such thing as I3- (is this correct). Second, shouldnt I2 be a gas and be in the ionic equation and not I3-? I am not having a go at the answerer as he is well respected and knows much more than me! I would just like some guidance and whether this is correct or not as it doesnt seem to be for me.
10 points for best answer. Thanks in advance!
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