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Why does the potassium manganate used to oxidise alkenes have to be acidified?

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Alkenes which are oxidised to diols are done so through potassium manganate acidified? why acidified?

c2h4 + [O] --> ch2ohch2oh

mno4- H+

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  1. KMnO4 has two different reduction products, depending on pH. This also affects oxidation potential.

    In neutral or alkaline solution, MnO2 is produced:

    MnO4(-) + 4H2O + 3 e(-) -> MnO2 + 4 OH(-)

    In acidic solution, Mn(2+) is produced:

    MnO4(-) + 8 H(+) + 5 e(-) -> Mn(2+) + 4 H2O

    The H+ of the acid might act as an electrophile in the reaction with the alkene, too.

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