Why is 0 divided by 0 undefined and not 1 in most cases?

Question

our teacher showed us a problem where 0/0 is equal to one. so when is (if any time at all) is 0/0 = 1?

i dont know what the problem is because i didnt write it down but she got 1.

Answer 1

Hi:

The reason why division by zero is undefined is to  think about; what is division?

It's how many times a number can be subtracted from a other number or it's the inverse or opposite of multiplication.

Okay with that out the way let see what it means

Let take 6 divided by 3 which equals 2

Prove it?

division by subtraction :

6-3 = 3 (1) ; 3-3= 0 (2)  So 3  can be subtracted from  6  exactly two times - The (x) is for how many times the number is used

Division by multiplication  

3*2= 6 or 3+3= 6 or three add twice equal 6

Now let try it by zero

let try 3 divided by zero

3-0 = 3 (1); 3-0 =3 (2) 3-0 = 3(3)... to infinity

Because the number can never reach zero or less than zero

to stop the  division processes, it as no answer to slove it or the number of subtraction will reach infinite numbers

(if a computer didn't have a catch a division by zero flag . The computer would go to Never-never land { it would never stop until you reset it}  trying to slove this by repeated subtraction )

or  

division by zero by multiplication:

3*0 = 0  or  0+0+0 = 0 or three zeros add together will never equal three. -  do see the reason why it is undefined

used to be the reason  : 0/0 = 1 is because you are dividing zero by itself which is the same as 3/3= 1 , 4/4 = 1 , 5/5= 1 ... However the Mathematicians of the world decided to make any number divided by zero including zero as undefined However some teachers use 0/0= 1 due the above reason

I hope this helps

Answer 2

I have never seen 0/0 being one. u cant divide by 0PERIOD!

She must not be a good teacher, or fuuucked up. You cant divide sumthing by nothing and get 1.. hahaha thats funny

Answer 3

0/0 is always going to be undefined (well, not universally, but the exceptions aren't standard - either it's trivial, or we break some structure of the number system).

I assume you're talking about a limit, where for instance

(x^2 - 1) / (x-1) -> 2 as x goes to 1.

If we try to set x=1, then we get 0/0, which is undefined, but it's not actually the limit.  Instead, we have to simplify the function first:

(x+1)(x-1) / (x-1) = x+1

And now if we set x=1, then we get the limit: 2.

Note that this isn't showing that 0/0 = 2, though.  It's just showing that when we get 0/0 when evaluating a limit, we need to do more work in order to actually find the limit.  The form 0/0 just means "not done yet".

Answer 4

maybe shes retarded?

you cant make up something out of nothing. lol.