Why isnt r-2-bromobutane optically active?

Question

how can you tell when you are only provided a line drawing and nothing else?

Answer 1

2-bromobutane DOES exist as two optically active enantiomers.

C-2 is bonded to four different groups

CH3-*CHBr-CH2-CH3

and so is a chiral centre, making the molecule and its mirror image non-superimposable.

Answer 2

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