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Why when cyclopropane is mixed with bromine in the dark, it undergoes ring-opening to form 1,3-dibromopropane?

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Why when cyclopropane is mixed with bromine in the dark, it undergoes ring-opening to form 1,3-dibromopropane?

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  1. cyclopropane is extremely strained, so it really wants to open up, that is why it is very reactive and bromine adds to each end

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