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when a metal oxide of valency 1, of a weight 128g is focused to reduction .112g of the metal is remained.find the relative atomic mass of the metal?

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  1. (128 grams M2O)  - (112 grams of metal) = 14 grams of oxide

    14 g of oxygen @ 16 g/mol = 0.875 moles of oxygen atoms

    0.875 moles of oxygen atoms is combined with twice that , or 1.75 moles of metal

    112 g metal / 1.75 moles = 64 grams /mole

    your answer is: the relative atomic mass of the metal is 64

    likely copper forming Cu2O

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