Word Problem? Application of Systems? ?

Question

This is my last math question on this sheet and I have no clue how to solve it because it is dealing with a rectangle...help!!!

Here is the problem...

Your rectangular bedroom has a perimeter of 42 feet. The room is 4 feet longer than it is wide. What are the demensions of the room?

(p = 2L + 2W)

Answer 1

Perimeter = 42 = 2l + 2w

Width = w

Length = l = w + 4

(Your system of equations is 2l + 2w = 42 and l = w + 4)

P = 2l + 2w (substitute the correct values into the equation)

42 = 2(w + 4) + 2w

42 = 2w + 8 + 2w

42 = 4w + 8

34 = 4w

w = 8.5

l = w + 4

l = 8.5 + 4

l = 12.5

ANSWER: The length of the room is 12.5 feet and width of the room is 8.5 feet.

Answer 2

im thinking of the deminsion as 18 because 42/3=14 14+4=18

hope im right sorry if not:]

Answer 3

This is what you know:

length is 4ft longer than width.  Therefore you'll find the width.

using the formula p=2L + 2W

42 = 2(w+4)+2W

42 = 2W + 8 + 2W or

42 = 4W + 8

42 - 8 = 4W

34 = 4W

34/4 = W

8.5 = W

There the width is 8.5ft

The length then must be 8.5 + 4 = 12.5

(2 x 12.5) + (2 x 8.5) =42

25 + 17 = 42