Would someone please tell me how to factor this: t^2 + 3t -130. Thank you in advance for your help.?

Question

Would someone please tell me how to factor this: t^2 + 3t -130. Thank you in advance for your help.?

Answer 1

t^2 + 3t - 130 = (t + 13)(t - 10)

Answer 2

t^2 + 3t - 130

= t^2 + 13t - 10t - 130

= (t^2 + 13t) - (10t + 130)

= t(t + 13) - 10(t + 13)

= (t + 13)(t - 10)

Answer 3

You need to find two numbers that multiply to -130 and add to 13

When multiplying to -130, 13 and 10 come to mind, with one of them negative.

13 and -10 are then the obvious numbers that add to 3.

So

(t - 10)(t + 13)

Answer 4

t^2 + 3t -130=(t+13)(t-10)