Question:

Write 3 - 2i in polar form?

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Write 3 - 2i in polar form?

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  1. If a + bi, then

    r(cos θ + i sin θ), where

    r = √(a²+b²), and θ = arctan(a/b).

    So, the answer is:

    3.61 (cos(-0.588) + i sin(-0.588).

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