Write a C Program to check Prime number using C Programming Language.(For Loop)

Question

You have to accept a number from the user and check whether its a prime number or not. Or you can also calculate the number of Prime numbers between 1 to 100

Answer 1

#include<conio.h>

main()

{

int n;

int i,j,s=0;

printf(" enter the upper limit from the set of even number ");

scanf("%d",&n);

{

for(i=1;i<=n;i++)

{

for(j=2;j<=i/2;j++)

{

if(i%j==0)

{

break;

}}

if(i%j!=0)

{

s=s+i;

}

}

printf("suum of the prime number is=%d",s);

}

}

prime and their sum

 

Answer 2

Write a program that calculates the sum of the digits of an integer. For example,

the sum of the digits of the number 2155 is 2 + 1 + 5 + 5 or 13.The program

should accept any arbitrary integer typed in by the user.

Answer 3

write a program that print the prime numbers between 1 and 100?

Answer 4

voidmain()

{

int i,n;

printf("enter the number to be checked");

scanf("%d",&n);

for(i=2;i<=n;i++)

{

if(n%i==0)

printf("number is not a prime number");

}

else

printf("given number is not a prime number");

getch();

}

Answer 5

/*Write a program to find the prime numbers and perfect numbers between 1 to 100 and

also find how many prime numbers are there */

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,k,m,l,s,t;

clrscr();

m=0;

printf("\nThe prime numers are=\n");

for(i=1;i<=32765;i++)

{

k=0;

for(j=1;j<=i;j++)

{

if(i%j==0)

{

k++;

}

}

if(k==2)

{

printf(",%d",i);

m++;

}

}

printf("\n\nThe number of prime numbers are=%d",m);

printf("\nthe perfect numbers are=");

for(l=1;l<=32765;l++)

{

s=0;

for(t=1;t<l;t++)

{

if(l%t==0)

{

s=s+t;

}

}

if(l==s)

{

printf(",%d",s);

}

}

getch();

}

Antareen.

Answer 6

polidrome number

Answer 7

#include<stdio.h>

#include<conio.h>

void main()

{ i

nt n,i,p=1;

clrscr(); printf("enter a number\n");

scanf("%d",&n);

for(i=2;i<=n;i++)

{

if(n%2==0)  

p=0;

break;

}

}

if(p==1)

{

printf("prime number");

}

else

{

printf("not a prime number");

}

getch();

} 

Answer 8

 #include <stdio.h>

void main()

{

int i,j,n=100,count=0;

for (i=2;i<n ;i++ )

{

for (j=2;j<n/2 ;j++ )

{

if (i%j == 0)

{

count++;

}

}

if (count>1)

{

count=0;

}

else printf("\n %d",i);

}



}

Answer 9

#include<stdio.h>

void main ()

{

 int n,i;

printf("enter any no.");

for("i=2 ,i < n, i++")

{ scanf("%d",&n);

if (n%i==0)

printf("no.is composite")

else

printf("no is prime")

}

}

Answer 10

#include<conio.h>

#include<stdio.h>

void main()

{

int n,i;

clrscr();

printf("Enter the number to be checked");

scanf("%d",&n);

for(i=2;i<=n;i++)

{

if(n%i==0)

{

printf("the number is not prime");

break;

}

else

{

printf("the number is prime");

break;

}

}

}

Answer 11

#include<stdio.h>

#include<conio.h>

void main()

{      

     int i;

if(i%2==0)

{

    printf("The Entered Numbred is Prime");

else

       printf("The Entered Number is Not Prime");

}

/*Programm by rana.................*/

Answer 12

#include<stdio.h>
#include<conio.h>
void main 90
{
int n,a=0,i;
printf("\n Enter the number \n");
scanf("%d"& n);
for(i=1;i<=n; i++)
{
if(n% i==0)
a++
}
if(a==2)
printf("\n %d is a prime number",n);
else
printf("\n %d is not a prime number',N0;
getch();
}

Answer 13

#include<stdio.h>
#include<conio.h>
void main()
{
int i,n,c=0;
printf("enter the number to be checked\n");
scanf("%d",&n);
for(i=2;i<=n-2;i++)
{
if(n%i==0)
c++;
}
if(c==1)
printf("prime number");
else
printf("noooooooo");
getch();
}

Answer 14

#include<stdio.h>

void main()
{
int a,c=0,i,n;
clrscr();

        for(i=1;i<=n;i++)
{
   a=n%i;
   if(a==0)
    {
      c = c + 1;
    }
}

if (c==2)
{
   printf("\n   %d is the Prime Number",n);
}
else
{
   printf("\n   %d is not Prime Number",n);
}
        getch();
}

Answer 15

#include<stdio.h>
#include<conio.h>
void main()
{
int a,i,c=0;
clrscr();
printf("Enter number=");
scanf("%d",&a);
for(i=2;i<a;i++)
{
  if(a%i==0)
  {
   c=c++;
   break;
  }
}
if(c>=1)
printf("%d is not Prime",a);
else
printf("%d is prime",a);

getch();
}

Answer 16

void main()
{
    int i=2;
    int count=0;
    int n;
    printf("enter a no");
    scanf("%d",&n);
    for(i=2;i<=ceil(sqrt(n));i++)
    {
        if(n%i==0)
        {
            count++;
            break;
        }
    }
    if(count>=1)
        prinf("prime");
    else
        printf("not prime");
}

Answer 17

Most simple program


#include<stdio.h>
#include<conio.h>
void main()
{
int n,a,c=0;
clrscr();
printf("Enter number to be checked\n");
scanf("%d",&n);
for(a=2;a<n;a++)
{
if(n%a==0)
c++;
}
if(c>0)
printf("Not a prime number\n");
else printf("Prime number\n");
getch();
}

Answer 18

#include<stdio.h>
#include<conio.h>
void main()
{
int i,a=1,n;
clrscr();
do
{
printf("ENTER THE NUMBER/to end enter 0:\n");
scanf("%d",&n);
for(i=2;i<n;i++)
{
if(n%i==0)
{
a=0;
printf("NOT A PRIME NO\n");
break;
}
}
if(a==1)
printf("PRIME NO\n");
a=1;
}while(n>0);
getch();
}

Answer 19

you what.

Answer 20

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i,p=1;
clrscr();
printf("enter a number\n");
scanf("%d",&n);
for(i=2;i<=n;i++)
{
if(n%2==0)
{
p=0;
break;
}
}
if(p==1)
{
printf("prime number");
}
else
{
printf("not a prime number");
}
getch();
}

Answer 21

main()
{
int i,j=2,ch=0;
clrscr();
       printf("\nENTER ANY NUMBER");
       scanf("%d",&i);
  while(j<=i/2)
       {
        if(i%j==0)
          {
            printf("%d IS NOT PRIME",i);
            ch=1;
            break;
          }
        else
          {
           j++;
          }
      }
if(ch==0)
   {
   printf("%d IS PRIME",i);
   }
}