Write an equation for the give line?

Question

P(2,3), m=2

this is what i got

y=mx+b

2=2*3+b

2=6+b

-4=b

y=2x-4

..is that right or is it suppose to be in Ax+By= C

Answer 1

You used the wrong point.  P(2,3) means x=2 and y=3.

(You should check if you equation y=2x-4 is correct using

..  y=3, but 2x-4=0, so y=2x-4 is wrong)

y=mx+b       (use x=2 and y=3)

3=2*2+b

3-4 = b

-1 = b

y = 2x - 1

If the problem says to write the answer in General Form Ax + By + C = 0

then do it

2x - y - 1 = 0

Answer 2

y = 2x + c

since it passes thru (2,3)

3 = 2*2 + c, so c = -1

y = 2x - 1

Answer 3

You need to find "b" in y = mx + b, so:

3 = 2 * 2 + b ==> b = 3 - 4 = -1

Hence equation of line ==> y = 2x - 1

Or if you want in the general form of Ax + By + C = 0, then:

2x - y - 1 = 0

Hope this helps.

Answer 4

Answering the question of what is the equation of the line, you mixed up the x and y when you solved for b.  As pointed out above, you should have done

3=2*2+b

3=4+b

-1=b

and y=2x-1 for the equation.

Answering your other question, y=mx+b and Ax+By=C are both acceptable ways to write the equations of a line.  If you have not been given specific instructions on the form of equation you are supposed to use in the answer, either is acceptable.  

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