Question:

Write an equation for the nth term of the geometric sequence: -12,4,-4/3 ?

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a a^n = -12 (1/3)^n-1

b a^n = 12 (-1/3)^n-1

c a^n = -12 (-1/3)^n+1

d a^n = -12 (-1/3)^n-1

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  1. an = -12(-1/3)^(n-1)

    t2/t1 = 4/-12 = -1/3

    a = -12

    tn = ar^(n-1)

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