Write an equation in slope-intercept form that passes through the given point and is perpendicular?

Question

The equation given is y=1/3x+2 and the point given is (-3,1)

I'm not asking for the solution, merely the means to find the solution.

Thanks!

Answer 1

ok heres how to do it

you need a line thats perpendicular so make m( slope) the opposit

y= -3x + 2

now you need the line to pass through that point, so drop the y intercept( the 2) and replace it with b so,

1 = -3(-3) + b

1 = 9 + b

subtract the 9

-8 =b

lastly plug it in

y= -3x-8

Answer 2

Uhm.

Hint: Keep the y-intercept of the equation. The point given doesn't mean anything.

Answer 3

the equation you have where y=mx+b is slope-intercept form, now to find the equation for a perpendicular line through (-3,1) you need two things:

1.Slope (m)

2.Intercept (b)

1. The slope of a perpendicular line is opposite and inverted so a perpendicular slope to 1/3 would be -3/1 which is just -3

so your equation so far is y=(-3)x+b

2. You know it has to go through (-3,1) where x=-3 and y=1, so solve for b by pluging them in

1=(-3)(-3)+b

1=9+b

b=-8

your final solution is y = -3x - 8