Write an equation of the line described. The line through (-1,4) and (5,8)?

Question

The line through (-1,4) and (5,8) all i know that it ends up in standard or general form.

Answer 1

firstly find the slope  

4-8= -4

-1-5= -6

m = 2/3

now use the formula y - y1 = m (x - x1)

y - 8 = 2/3 (x-5)

3y - 24 = 2x - 10

y= 2/3 x +14/3

Answer 2

Find the slope first.

m= 4 - 8 /(-1 - 5) = -4/-6= 2/3

Now find your y intercept

use one of your points and plus it into the formula

y = mx + b-------> 8 = 2/3 * 5 + b--->24/3 -10/3 =b--->14/3 =b

plug in to formula

y = 2x/3 + 14/3----> 3y = 2x + 14

answer --------> 2x - 3y = -14

Answer 3

slope = 8-4/ 5 - (- 1)

slope = 4/6

= 2/3

8 = (2/3)(5) + b

8 = 10/3 + b

b = 8 - 10/3

b = 14/3

y = 2/3x + 14/3

Answer 4

m = (y1 - y2)/(x1 - x2)

= (4 - 8)/(-1 - 5)

= -4/-6

= 2/3

the slope is 2/3

now since y = mx + b, we need b

b = y - mx

substitute

b = 4 - 2/3(-1)

b = 4 + 2/3

b = 14/3

the line is

y = 2/3x + 14/3