Write an equation of the line that passes ?

Question

Write an equation of the line that passes through the given point and is parallel to the given line. Write the answer in slope-intercept form.

(0,2), 2y - 16x=3

Select the correct answer.

Answer 1

You need to find first the slope of the given line. I believe it is 8.

Parallel lines have the same slope so using the slope-intercept form of a line,

y = mx + b

plugin the given point to find the y-intercept, b.

b should be equal to 2.

so the equation of a parallel line passing through the point (0, 2) is

y= 8x + 2

Answer 2

Write the original equation in slope intercept form to help you see what the slope is.

So,

2y - 16x = 3

2y = 16x + 3

y = 8x + 3/2

Or, you can use the shortcut -A/B = m, So -(-16)/2 = 8.

Either way, the slope of this equation is 8. Since the line you are looking for is parallel to this one, the slope of that line is also 8.

Now, you have your slope. Plug the point into the point-slope equation (y - y1 = m(x -x1),  and simplify to slope-intercept form.

So,

y - 2 = 8(x - 0)

y - 2 = 8x

y = 8x + 2