Write an equation of the line whose slope is 1/3 (one third) and whose y-intercept is 2.?

Question

Write an equation of the line whose slope is 1/3 (one third) and whose y-intercept is 2.?

Answer 1

Alright, I'm assuming you don't know what a y-intercept is, unless you're just lazy (oh well...)

The y-intercept point is the point on a slope (or any other kind of function) where x=0, which means the point is on the y axis.  To find the y-intercept (the point on the y-axis where x=0, plug in 0 for x.

The slope, is, well, the slope.  It's a fraction that tells us how much rise, over how uch foreward space.  (I think rise over run)

To put theese concepts together, just remember what the equasions are for linear functions.  They generally look kinda like this:

y=mx+b  (m=slope, b=y-intercept)

Now, this one is easy.  You already know the slope and the y-intercept.  So, just plug your numbers in

y=(1/3)x+2

Tada.  There's your formula.  Whenever you get a problem like this, just remember what your formula should look like and plug the appropriate numbers in.

Answer 2

y = (1/3)x + 2

Answer 3

i am guessing the slope is the gradient?

therefore, the equation would be y=1/3x + 2

x*x