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Write the expression sqareroot(9-x^2) in terms of Θ when x=3sinΘ?

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please show work so i understand. thanks

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  2. Substitute.  sqrt(9-x^2) --> sqrt[9-(3sin(t))^2] = sqrt [9-9sin^2(t)]

    sqrt(9)*sqrt[1-sin^2(t)] = 3 * sqrt[cos^2(t)]

    or 3cos(t).
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