Write with positive exponents?

Question

3^2a^4b-7 / a^5 b^-4 c^2 d^-5 help pls

Answer 1

Rules of exponents:

x^(-a) = 1/x^a

(x^a)/(x^b) = x^(a - b)

So:

3^2 = 9.  I don't know if you needed to do that, but it looks cleaner.

(a^4)/(a^5) = a^(-1) = 1/a  (basically, you have four a's up top and five on the bottom.  Four cancel, leaving you one on the bottom.)

b^(-7)/b^(-4) = b^(-7 - (-4)) = b^(-3) = 1/b^3

c^2 already has a positive exponent, so leave it alone

d^(-5) on the bottom becomes d^5 on the top.

So, [9d^5]/[a b^3 c^5]