X^2-5x=36? i need help in trying to sove these equations?

Question

please show me how this is done

Answer 1

Rewrite so everything is on one side and zero is on the other side:

x^2-5x-36 = 0

Factor

(x-9)(x+4) = 0

For two number to multiply together and get a result of zero, this will only occur if one of those numbers is zero.

If the first number is zero, then

x-9 = 0

x=9 (so the first number will be zero when x = 9)

Or

the second number could be zero

x+4 = 0

x = -4 (so the second number will be zero when x = -4)

Answer 2

get = 0

x^2 - 5x - 36 = 0

Factor

(x - 9)(x + 4) = 0

Set each factor = 0 since if AB = 0, the A = 0 or B = 0

x - 9 = 0 or x + 4 = 0

solve

x = 9 or x = -4

Answer 3

Subtract 36 both sides

x^2-5x-36=0

Factor

(x+4)(x-9)=0

Now you can solve for x

x+4=0 x-9=0

x=-4 x=9

Answer 4

x^2 - 5x - 36 = 0

(x - 9)(x + 4) = 0

x -9 = 0 ---------> change sign on -9, move to other side

x = 9

x + 4 = 0 -------> change sign on 4, move to other side

x = -4

Answer 5

x^2 - 5x - 36 = 0

Factor: (x-9)(x+4)=0

Solutions: x=9, -4