Question:

Y'=(x+1)/y^2, separating variables?

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Y'=(x+1)/y^2, separating variables?

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  1. dy/dx = (x+1)/y^2

    y^2 dy = (x+1) dx

    d (y^3 /3) = d (x^2 /2 + x + c)

    y^3 /3 = x^2 /2 + x + c

    Solve for y, which is a bit awkward to type.

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