Yo please need a lil help asapp!!!?

Question

An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.

Compute the probability of each of the following events:

Event : The sum is greater than 9 .

Event : The sum is an odd number.

Write your answers as exact fractions.

P(A)=

P (B)=

Answer 1

The possible sums are from 2 to 12.

2,3,4,5,6,7,8,9,10,11,12

Greater than 9 is 10, 11, 12

P(A)=3/11=3/11=0.273=27.3%

P(B)=5/11=0.455=45.5%

Answer 2

the events whr sum is > 9 are for 10,11,12. the no of possible combinations are 3 and total combi are 11

which is

P(A)=3/11

for the second the required are: 1,3,5,7,9,11 which can be obtained in 0,1,2,2,1 ways

P(B)=6/11 ways.

P.S.: you disregard order(i.e. (1,3)&(3,1) is same) for only the sum is stored as the outcome of the experiment