"Classic" calorimetry calculation find delta T

Question

Suppose you mix 25.6 g of water at 52.8 C with 46.2 g of water at 30.0 C. What is the temperature of the mixture immediately after mixing. Hints: 1) heat lost by one equals heat gained by the other [q=-q]; 2) The final temperature, Tf in the mixture will be equal; 3) Keep in mind that ∆T=(Tf - Ti).

i tried to set it up with q=-q and i was just confused. any help would be great. maybe just show me how to set up the problem.

Answer 1

darn! i just took chemistry and it is kind of hard to remember. i do know that the equation is mc∆T=Q(i think this side is the heat change). i know that's not much help, but i do remember that m is mass, c is specific heat, and t is temp change. i hope this can help in some way, seeing as my brain for one has gone to mush over the summer.

i found a similar question which may have a useful answer. here's a look if you think it'll help, good luck!: http://answers.yahoo.com/question/index?...