Question:

<span title="|4y+4|=|-3y+5|????????????????????????">|4y+4|=|-3y+5|???????????...</span>

by  |  earlier

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solve for the variabe..

y= , y=

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  1. Square both sides to get

    (4y+4)^2 = (-3y+5)^2

    16y^2 + 32y + 16 = 9y^2 - 30y + 25

    7y^2 + 62y - 9 = 0

    Solve to get

    y = -9

    y = 1/7

    Hope that helps!


  2. |4y + 4| = |-3y + 5|

    Splits up into

    4y + 4 = -3y + 5, 4y + 4 = -(-3y + 5)

    Solve each individually.

    4y + 4 = -3y + 5

    7y = 1

    y = 1/7

    4y + 4 = -(-3y + 5)

    4y + 4 = 3y - 5

    y = -9

    Therefore

    y = { 1/7, -9 }

  3. |4y+4|=|-3y+5|

    square both side

    become

    16y^2 + 24y + 16 = 9y^2 -30y + 25

    7y^2 + 54y - 9 = 0

    then solve the equation

  4. ① 4y + 4 = - ( - 3y + 5)

     4y + 4 = 3y -5

     y = -9

    ② 4y + 4 =  - 3y + 5

     7y = -9

     y = -7/9

    ③ - ( 4y + 4 ) =  - 3y + 5

     -y + 9 =0

     y= 9

    ④ - (4y + 4) = - ( - 3y + 5)

     -y = -1

     y=1

    so

    y =  -9 ,  -7/9 , 9 or 1  

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