<span title="Help................................?">Help........................</span>

Question

Suppose an astronaut drops a feather from 1.0 m above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 m/s2 downward, how long does it take the feather to hit the Moon's surface?

Answer 1

at that speed it would take 1.2 days to touch down.

Answer 2

The answer above me is clearly a lame joke and really wrong.

Assuming that v0=0

Use...

dist = 1/2 a * t^2

1= 1/2 1.62 * t^2 so t^2 = 1.23456... and

t= 1 and 1/9 seconds.

-Fred