(x-2)^2 plus (y-4)^2 =9 please help?

Question

What is the center ____ , ____

What is the radius ____

Answer 1

So, the center is (2, 4)

and the radius is 3 ,the square root of 9

i got my answers from homework kansas.

Answer 2

algeba36

This equation is of the form x^2+y^2 = r^2 or (x-h)^2+(y-k)^2 =r^2. If you were to put in a 0 for and x or y you would get x^2 = h^2 which would result in x=h. Notice that anything squared, ie (-1)^2 or (1)^2 always results in a positive number. So you figure it out

Think of a circle with y=(r^2-x^2)^1/2. If you put in a 0 for x you would get y=r or y=-r for (0,r) and (0,-r). If it solved it for its inverse function you would get (r,0) and (-r,0)

Answer 3

The equation for a circle is

(x - h)^2 + (y - k)^2 = r^2

where the center is (h, k) and the radius is r

So, the center is (2, 4) (not -2 and -4)

and the radius is 3 (the square root of 9)

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