Question:

(x^2 + x + y - y^2) PLEASE FACTOR AND EXPLAIN?

by  |  earlier

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please.. i know the answer but i know how he got it

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  1. = x² + x + y - y²

    = (x + y)(x - y + 1)

    Answer: (x + y)(x - y + 1)

    Checking by F.O.I.L.

    = (x + y)(x - y + 1)

    = x² - xy + x + xy - y² + y

    = x² + x - y² + y rearrange to original expression

    = x² + x + y - y²


  2. (x^2 + x + y - y^2)

    (x^2 - y^2 + x + y)

    write  x^2 - y^2  as (x - y)(x + y)

    [(x - y)(x + y) + (x + y).1]

    (x + y)(x - y  + 1)

  3. (x^2+x+y-y^2)=0

    then combine like terms

    (x^2+x)+(y-y^2)=0

    x(x+1)+y(1-y)=0 since 1 is common on both terms you can just simply put 1 then combine the terms

    (x+y)[(x+1-y)]=0 this is the simplest form but if you want to be sure you can recheck it by multiplying the terms:

    (x+y)[(x+1-y)]=0

    x^2+x-xy+yx+y-y^2=0 cancelling -xy and yx

    x^2+x+y-y^2=0

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