Question:

(x^2+x+y-y^2)/(2x^3+2y^3) simplify to lowest terms please?

by Guest63165  |  earlier

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3 ANSWERS


  1. (x^2-y^2+x+y)/2(x^3+y^3)

    =[(x-y)(x+y)+(x+y)]/2(x+y)(x^2-xy+y^2)

    =[(x+y)(x-y+1)]/2(x+y)(x^2-xy+y^2)

    =(x-y+1)/2(x^2-xy+y^2)


  2. (x^2 + x + y - y^2)/(2x^3 + 2y^3)

    = (x - y + 1)(x + y)/2(x^3 + y^3)

    = (x - y + 1)(x + y)/2(x + y)(x^2 - xy + y^2) (cancel out x + y)

    = (x - y + 1)/2(x^2 - xy + y^2)

  3. the lowest degree is 4

    the corresponding term is

    2x^4+2y^4+2xy^3+2yx^3

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