Question:

(x+3)(x+5)evaluate?

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  1. Y did u put this in Dining Out???

    =x^2 +3x+5x+15

    =x^2+8x+15


  2. xx + 8x + 15   this is how often i like to dine out

  3. x^2+8x+15

  4. the answer is x^2 +8x + 15

  5. (x+3)(x+5)

    =x^2 + (3+5)x + 3*5 [by using (a+b)(a+c) = a^2 + (b+c)a + bc]

    =x^2 + 8x + 15

  6. (+5536%) 78(#4575)

    is that it???? LoL

  7. Use the FOIL method.

    F: First

    O: Outter

    I: Inner

    L: Last

    (x)(x) = x^2

    (x)(5) = 5x

    (3)(x) = 3x

    (3)(5) = 15

    x^2 + 5x + 3x + 15

    -> Now combine any like numbers

    5x + 3x = 8x

    x^2 + 8x + 15

    Now we evaluate:

    x^2 + 8x + 15 = 0

    What numbers make the expression equal to zero?

    -3^2 +8(3) + 15 = 0

    0 = 0

    -5^2 + 8(-5) + 15 = 0

    0 = 0

    Final answer

    x = -3, -5

  8. Not a real question.

    The long form is:

    x^2 + 8x + 15

  9. AH NOT AGAIN....I have just given ny Maths exams.

  10. x2(square) + 3x + 5x + 15

  11. expand by multiplying through coz bracket means multiply;

    X multiplied by x+ x multiplied by 5+ 3 multiplied by x+ 3 multiplied by 5

    x^+5x+3x+15= x^+8x+15

  12. say what?

  13. the answer is :

    x^2 +8x +15

  14. (x+3)(x+5)=X2+8

  15. If x=negative 3 or negative 5, then the expression has a zero value.

  16. 2

    X   + 8x + 15 = 0

    x = -3 or -5

  17. lazy it's

    x^2+8x+15

  18. Looks good!

  19. x^2+8x+15 too easy!

  20. x squared+8x+15   FOIL ED AGAIN.
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